Which one of the following has a square planar geometry? If you are on a personal connection, like at home, you can run an anti-virus scan on your device to make sure it is not infected with malware. I found ["Co"("ox")_2("OH")_2]^(-) to have four unpaired electrons. 0 unpaired electron. So the complex having highest paramagnetism would be the complex of iron containing four unpaired electrons. (i) It is a neutral ligand. Paramagnetism is a form of magnetism whereby some materials are weakly attracted by an externally applied magnetic field, and form internal, induced magnetic fields in the direction of the applied magnetic field. D) chiral. (ii)A transition metal exhibits highest oxidation state in oxides and fluorides. At. "ox" is oxalato, a -2 bidentate ligand. Jan 17,2021 - Which of the following complex compounds will exhibit highest paramagnetic behaviour? Which of the following complexes exhibits the highest paramagnetic behaviour? (a) [Co(ox)2(OH)2]- (b) [Ti(NH3)6]3 (c) [V(gly)2(OH)2(NH3)2] (d) [Fe(en)(bpy)(NH3)2]2? Which of the following complexes exhibits the highest paramagnetic behaviour? Hence, [Co (OX) 2 (OH) 2] - has highest paramagnetic behaviour. All electrons will be paired in this low spin complex so it will be diamagnetic. [V … "gly" is glycine, a neutral ligand at "pH" 7. - The geometric isomers of the complex ion have identical chemical properties. This means that the iron must be +2 in its complex. Which of the following complexes exhibits the highest paramagnetic behaviour ? where, gly = glycine, en = ethylenediamine and bpy = bipyridyl moities) (At. Can you explain this answer? where gly=glycine, en=ethylenediamine and bipy =bipyridyl (At. (ii) Cr2+ is a strong reducing agent. Which of the following complexes exhibits the highest paramagnetic behaviour? (ii) Transition metals form a large number of complexes. (a) [Co(ox)2(OH)2]^- - 7946492 MaheraHyatKhan3560 MaheraHyatKhan3560 02.02.2019 Science Secondary School Which of the following complexes exhibits the highest paramagnetic behaviour? Join now. It should be an inner orbital complex (d2sp3 hybridisation) containing only one unpaired electron. Most of them are paramagnetic. All electrons will be paired in this low spin complex so it will be diamagnetic. Cloudflare Ray ID: 615924dbaf86ea45 Transition elements having partly filled d-orbitals exhibit several interesting properties. E) Most of the elements, upon ionizing, lose the d electrons first. The complex having d 2 sp 3 hybridization is an “inner shell” complex, while the complex with sp 3 d 2 hybridization is an “outer shell” complex. Total charge from CN is -6. when the number of unpaired valence electrons increases, the d-orbital increase & the highest oxidation state increases. In which of the following octahedral complexes of Co (at. `Ti=22, V=23, Fe=26, Co=27`) Click hereto get an answer to your question ️ Which of the following complex compounds will exhibit highest paramagnetic behaviour? Hence, K will also be higher among these four, i.e., stability of the complexes will be highest among these four complexes. There is no actual difference; the orbitals involved are the same, only listed in a different order. C) Most of the metals exhibit multiple oxidation states. O.S of Ti in the complex [Ti (NH3)6]3+. Hence, [NiCl 4] 2− is paramagnetic.. (Where gly = glycine, en = ethylenediamine and bpy = bipyridyl moities). Cr = 24, ... AIEEE 2005. The most likely explanation for this is: A) Zn2+ is paramagnetic. • `Ti=22, V=23, Fe=26, Co=27`) Remember that molecules such as O 2 that contain unpaired electrons are paramagnetic. In the transition metals, the stability of higher oxidation states increases down a column. Ask your question. Log in. (At. (a) [V(gly)₂(OH)₂(NH₃)₂]⁺ (b) [… Get the answers you need, now! no. - Because en is a strong field ligand (large Δ), the complex ion is paramagnetic. Which of the following complexes exhibits the highest paramagnetic behaviour? Which of the following complex compounds will exhibit highest paramagnetic behaviour? Transition metals … • [2011M] (At. • 40. Can you explain this answer? e. [Fe(CN)6]4- (low spin) Charge on CN is -1. (a) [Co(ox)2(OH)2]^- 1 See answer MaheraHyatKhan3560 is waiting for your help. nos. Greater is the number of unpaired electrons, larger is the paramagnetism. 32.Account for the following: (i) Mn shows the highest oxidation state of +7 with oxygen but with fluorine it shows the highest oxidation state of +4. no. … Yes, its paramagnetic. Answer: (i) Transition metals show paramagnetic behaviour. In the presence of strong field ligand NH3, pairing of electrons takes place and thus, octahedral complex, [Co(NH3)6]3+ is diamagnetic. Which of the following complexes exhibits the highest paramagnetic behaviour? Paramagnetism arises due to the presence of unpaired electrons with each electron having a magnetic moment associated with its spin angular momentum and orbital angular momentum. I would first reference your text to check the charge of the ligands, but you would have to memorize these in an exam. The highest oxidation state of a metal is exhibited in its oxide or fluoride due to its high electronegativity, low ionisation energy and small size. Which of the following complexes exhibits the highest paramagnetic behaviour ? If you are on a personal connection, like at home, you can run an anti-virus scan on your device to make sure it is not infected with malware. Performance & security by Cloudflare, Please complete the security check to access. No. No. 52.Which of the following complexes can exhibit optical isomerism? of Ti = 22, V =23,Fe =26, Co = 27) (a), log k = 6 (b) , log k = 27.3 (c) , log K=15.4 (d) , log K = 8.9 View Answer play_arrow; question_answer44) The colour of the coordination compounds depends on the crystal field splitting. करता है ? Cental metal atom in the compound having less number of unpaired electrons has the lowest value of paramagnetic behavior. (At. where, gly = glycine, en = ethylenediamine and bpy = bipyridyl moities) (At. Please enable Cookies and reload the page. • 40. : Ti = 22, Cr = 24, Co = 27, Zn = 30 If you are at an office or shared network, you can ask the network administrator to run a scan across the network looking for misconfigured or infected devices. : Ti = 22, Cr = 24, Co = 27, Zn = 30)a)[Ti (NH3)6]3+b)[Cr (NH3)6]3+c)[Co (NH3)6]3+d)[Zn (NH3)6]2+Correct answer is option 'B'. to Q.9 (ii). Q. Your IP: 185.43.44.104 ... Manganese exhibits the highest oxidation state of+7 among the 3d series of transition elements Answer: (i) Refer Ans. Another way to prevent getting this page in the future is to use Privacy Pass. Jan 02,2021 - Which of the following complexes exhibits the highest paramagnetic behaviour? Fe^2+ has a valence electron configuration of 3d^6. Co 5+ = [Ar]3d 4. (iii) The highest oxidation state is exhibited in oxoanions of a metal. no. (Where gly = glycine, en = ethylenediamine and bpy = bipyridyl moities). Which of the following complexes exhibits the highest paramagnetic behaviour? Which one of the following cyano complexes would exhibit the lowest value of paramagnetic behaviour? no. no. e. [Fe(CN)6]4- (low spin) Charge on CN is -1. : Ti = 22, Cr = 24, Co = 27, Zn = 30 ) | EduRev Class 12 Question is disucussed on EduRev Study Group by 121 Class 12 … Since it has a carboxyl group, it is … (i) It is a neutral ligand. 27), will the magnitude of $$\Delta _o$$ be the highest? "ox" is oxalato, a -2 bidentate ligand. Cl − is a weak field ligand and it does not cause the pairing of unpaired 3d electrons. Please enable Cookies and reload the page. Assign reason for each of the following : (i) Transition elements exhibit paramagnetic behaviour. However, in the first transition series, the orbital angular momentum is quenched. asked Oct 14, 2018 in Co-ordinations compound by Sagarmatha ( 54.4k points) d-and f- block elements Ti = 22, V = 23, Fe = 26, (2008) Co = 27) coordination entities the And best of luck for jee'17. Outer orbital complex utilises 3d-orbitals for bonding and exhibit paramagnetic behaviour, only if there present unpaired electrons. Me too appearing the exam. Here the question is asking to determine the complex compound which shows the lowest paramagnetic behaviour. This preview shows page 17 - 20 out of 40 pages.. 73. Many transition metal complexes have unpaired electrons and hence are paramagnetic. Jan 13,2021 - Which of the following complexes exhibits the highest paramagnetic behaviour ? (i) ... Identify the correct statements for the behaviour of ethane-1, 2-diamine as a ligand. Your IP: 67.227.193.73 The DNA cleavage profile demonstrated that both complexes perform non-random double-strand cleavage by following first‒order kinetics (kobs = 0.9432 min-1 for 1a and kobs = 0.6574 min-1 for 1b). That would make it the most paramagnetic. In contrast with this behavior, diamagnetic materials are repelled by magnetic fields and form induced magnetic fields in the direction opposite to that of the applied magnetic field. I found ["Co"("ox")_2("OH")_2]^(-) to have four unpaired electrons. is easily oxidised in the presence of a strong ligand. Performance & security by Cloudflare, Please complete the security check to access. Contents1 Important Questions for CBSE Class 12 Chemistry – Coordination Compounds1.1 PREVIOUS YEARS QUESTIONS1.2 20151.3 Very Short Answer Type Question [1 Mark]1.4 Short Answer Type Questions [I] [2 Marks]1.5 Short Answer Type Questions [II] [3 Marks]1.6 20141.7 Very Short Answer Type Questions [1 Mark]1.8 Short Answer Type Questions [l] [2 Marks]1.9 20131.10 Short Answer Type […] I have a naming guide here. The colour of the coordination compounds depends on the crystal field splitting. The complex ions of Zn2+ are all colorless. Which of the following complexes exhibits the highest paramagnetic behaviour? ]3+ (c) [V(gly)2(OH)2(NH3)2] (d) [Fe(en)(bpy)(NH3)2]2+ where gly = glycine, en = ethylenediamine and bpy = bipyridyl moities. (i) Because of the ability of oxygen to form multiple bond with Mn and single bond with fluorine. The value is negative hence μ eff is less than μ s.o of iron four... Please complete the security check to access is no actual difference ; the involved... 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